Longest Word Coderbyte Solution


Have the function LongestWord(sen) take the sen parameter being passed and return the longest word in the string. If there are two or more words that are the same length, return the first word from the string with that length. Ignore punctuation and assume sen will not be empty. Words may also contain numbers, for example, "Hello world123 567".



Input: "fun&!! time"

 Output: time

 Input: "I love dogs"

 Output: love

Longest Word Coderbyte Solution in Java

public class LongestWord {

final String ALPHABET =


String LongestWord(String sen) {
String[] words = sen.split("\\s");
String longestWord = null;
int longestWordLength = 0;

for (String word : words) {
int wordLength =
if (longestWord == null || wordLength > longestWordLength) {
longestWord = word;
longestWordLength = wordLength;

return longestWord;

int getWordLength(String str) {
int length = 0;

for (char c : str.toCharArray()) {
if (ALPHABET.indexOf(c) > -1 || ALPHABET_UPPER.indexOf(c) > -1) {
return length;

public static void main (String[] args) {
// keep this function call here
Scanner s = new Scanner(System.in);
LongestWord c = new LongestWord();

Longest Word Coderbyte Solution in JavaScript

function LongestWord(sen) {
var arr = sen.replace(/[^a-zA-Z ]/g,"").split(" ");
arr.sort(function(a,b) { return b.length - a.length } );
return arr.shift();



When working on the solution, you have to be aware of the directions that say to ignore punctuation. That means we need to strip out everything in the string except for the letters a-z and space.  Once removed, I am going to use the sort() function for Array to sort each word by the length in descending order. The first entry in the array is the longest word.

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