Have the function MultipleBrackets(str) take the str parameter being passed and return 1 #ofBrackets if the brackets are correctly matched and each one is accounted for. Otherwise, return 0.
For example: if str is "(hello [world])(!)", then the output should be 1 3 because all the brackets are matched and there are 3 pairs of brackets, but if str is "((hello [world])" the output should be 0 because the brackets do not correctly match up.Only "(", ")", "[", and "]" will be used as brackets. If str contains no brackets return 1.
Multiple Brackets Coderbyte Solution
import java.util.Scanner;
public class MultipleBrackets {
String MultipleBrackets(String str) {
int openBrackets = 0, openSquareBrackets = 0;
int nrOfBrackets = 0;
for (char c : str.toCharArray()) {
if (c == '(') {
openBrackets++;
nrOfBrackets++;
} else if (c == '[') {
openSquareBrackets++;
nrOfBrackets++;
} else if (c == ')' && openBrackets > 0) {
openBrackets--;
} else if (c == ']' && openSquareBrackets > 0) {
openSquareBrackets--;
} else if (c == ')' || c == ']') {
return "0";
}
}
return openBrackets == 0 &&
openSquareBrackets == 0 ? "1 " +
nrOfBrackets : "0";
}
public static void main (String[] args) {
// keep this function call here
Scanner s = new Scanner(System.in);
MultipleBrackets c = new MultipleBrackets();
System.out.print(c.MultipleBrackets(s.nextLine()));
}
}
