Have the function PalindromeTwo(str) take the str parameter being passed and return the string true if the parameter is a palindrome, (the string is the same forward as it is backward) otherwise return the string false. The parameter entered may have punctuation and symbols but they should not affect whether the string is in fact a palindrome. For example: "Anne, I vote more cars race Rome-to-Vienna" should return true.
Palindrome Two Coderbyte Solution In Java
import java.util.Scanner;
public class PalindromeTwo {
boolean PalindromeTwo(String str) {
String stripped = strip(str);
String reversed = new StringBuilder(stripped).reverse().
toString();
return stripped.equals(reversed);
}
String strip(String str) {
StringBuilder result = new StringBuilder("");
for (char c : str.toCharArray()) {
if (Character.isLetter(c)) {
result.append(Character.toLowerCase(c));
}
}
return result.toString();
}
public static void main (String[] args) {
// keep this function call here
Scanner s = new Scanner(System.in);
PalindromeTwo c = new PalindromeTwo();
System.out.print(c.PalindromeTwo(s.nextLine()));
}
}
Palindrome Two Coderbyte Solution In JavaScript
function PalindromeTwo(str) {
var re = /[a-zA-Z]/;
var arr = [];
for(var i=0; i<str.length; i++){
if(str.charAt(i).match(re)){
arr.push(str.charAt(i).toLowerCase());
}
}
var hold = arr.join("");
arr = arr.reverse().join("");
if(arr==hold){
return true;
}
else{
return false;
}
}
