Have the function SimpleMode(arr) take the array of numbers stored in arr and return the number that appears most frequently (the mode).
For example: if arr contains [10, 4, 5, 2, 4] the output should be 4. If there is more than one mode return the one that appeared in the array first (ie. [5, 10, 10, 6, 5] should return 5 because it appeared first). If there is no mode return -1. The array will not be empty.
Simple mode coderbyte java
import java.util.Scanner;
public class SimpleMode {
int SimpleMode(int[] arr) {
int mode = 0;
int numCount = 0, highestCount = 0;
for (int i = 0; i < arr.length; i++) {
for (int j = 0; j < arr.length; j++) {
if (j == i || arr[i] == arr[j]) {
numCount++;
}
}
if (numCount > highestCount) {
mode = arr[i];
highestCount = numCount;
}
numCount = 0;
}
return highestCount > 1 ? mode : -1;
}
public static void main (String[] args) {
// keep this function call here
Scanner s = new Scanner(System.in);
SimpleMode c = new SimpleMode();
System.out.print(c.SimpleMode(new int[] {2,2,2,5,5,5,6}));
}
}
Simple mode coderbyte python
def SimpleMode(arr):
Aset = set(arr)
modeC = 1
modeN = 0
for i in Aset:
count = arr.count(i)
if count > modeC:
modeC = count
modeN = i
return modeN if modeC != 1 else -1
# keep this function call here
# to see how to enter arguments in Python scroll down
print SimpleMode(raw_input())
