# Counting Minutes I Coderbyte Solution

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Have the function CountingMinutesI(str) take the str parameter being passed which will be two times (each properly formatted with a colon and am or pm) separated by a hyphen and return the total number of minutes between the two times. The time will be in a 12 hour clock format.

For example: if str is 9:00am-10:00am then the output should be 60. If str is 1:00pm-11:00am the output should be 1320.

## Counting Minutes Coderbyte Java

import java.util.Scanner;

public class CountingMinutesOne {
final int MINUTES_IN_HOUR = 60;
final int MINUTES_IN_DAY = 24 * 60;

int CountingMinutesI(String str) {
String[] times = str.split("-");

int startTime = getMinuteOfDay(times);
int endTime = getMinuteOfDay(times);

return getDiff(startTime, endTime);

}

int getMinuteOfDay(String time) {
String[] parts = time.split(":");
int hour = Integer.parseInt(parts);
int min = Integer.parseInt(parts
.substring(0, parts.length() - 2));
int minOfDay = time.toLowerCase().contains("pm") ?
(hour * MINUTES_IN_HOUR) + min + (MINUTES_IN_DAY / 2) :
(hour * MINUTES_IN_HOUR) + min;
return minOfDay > MINUTES_IN_DAY ? minOfDay - MINUTES_IN_DAY :
minOfDay;
}

int getDiff(int startTime, int endTime) {
if (startTime <= endTime) return endTime - startTime;
return (MINUTES_IN_DAY - startTime) + endTime;
}

public static void main (String[] args) {
// keep this function call here
Scanner s = new Scanner(System.in);
CountingMinutesOne c = new CountingMinutesOne();
System.out.print(c.CountingMinutesI(s.nextLine()));
}
}

## Counting Minutes Coderbyte JavaScript

Using the JavaScript language, have the function CountingMinutesI(str) take the str parameter being passed which will be two times (each properly formatted with a colon and am or pm) separated by a hyphen and return the total number of minutes between the two times. The time will be in a 12 hour clock format.

For example: if str is 9:00am-10:00am then the output should be 60. If str is 1:00pm-11:00am the output should be 1320.

function CountingMinutesI(str) {
var time1Obj = {}, time2Obj = {}, timeDiff;
time1Obj = setTimeObject(str, 0);
time2Obj = setTimeObject(str, 1);
if (time1Obj.ampm == time2Obj.ampm && time1Obj.tot > time2Obj.tot) {
timeDiff = (((12 - time1Obj.hours + 12) * 60) - (time1Obj.mins)) + ((time2Obj.hours * 60) + time2Obj.mins);
}
else if (time1Obj.ampm == time2Obj.ampm && time1Obj.tot < time2Obj.tot) {
timeDiff = ((time2Obj.hours * 60) + time2Obj.mins) - ((time1Obj.hours * 60) + time1Obj.mins);
}
else if (time1Obj.ampm !== time2Obj.ampm && time1Obj.ampm === "am") {
timeDiff = (((12 - time1Obj.hours) * 60) - time1Obj.mins) + ((time2Obj.hours * 60) + time2Obj.mins);
}
else {
timeDiff = (((12 - time1Obj.hours) * 60) - time1Obj.mins) + ((time2Obj.hours * 60) + time2Obj.mins);
}

return timeDiff;
}
function setTimeObject(str, num) {
var arr = str.split("-");
var tObject = {};
tObject.hours = Number(arr[num].slice(0,arr[num].length-2).split(":"));
tObject.mins = Number(arr[num].slice(0,arr[num].length-2).split(":"));
tObject.ampm = arr[num].slice(-2);
tObject.tot = tObject.hours * 100 + tObject.mins;
}

#### Explanation:

Sometimes it pays to spend more time mapping out all the possibilites you might face in solving a problem before you start programming. This challenge will have 4 possible scenarios. They are:                                                     *

a) both have same ampm values and first time is after second time

b) both have same ampm values and the first time is before second time

c) have different ampm times and time1 is am

d) have different ampm times and time2 is pm

use an object to represent both times simply because I like to use words like hours, mins, and ampm instead of referring to an array index. To parse the str into the two time objects I created a separate function. Now that I have my 2 time object I just need to create a series of IF statements to correspond to the 4 scenarios listed above to calculate the timeDiff.

Disclaimer: The above Problem is generated by Coderbyte but the Solution is provided by ShouterFolk.