This is one of the easiest challenge in hacker rank regarding loops concept. In this challenge you will go through loops to solve this problem.Looping in programming languages is a feature which facilitates the execution of a set of instructions/functions repeatedly while some condition evaluates to true. While all the ways provide similar basic functionality, they differ in their syntax and condition checking time.
Challenge difficulty level: easy
Maximum score: 10
Task description:
Given an integer N print its first 10 multiples. Each multiple N * i(where 1 <=i <=10) should be printed on a new line in the form: N * i = result.
Input format
A single integer, N
Constraints
2<=N<=20
output format
print 10 lines of output each line i(where 1<=i<=10) contains the result of N * i in the form:
n * i = result
Sample input
2
sample output
2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20
Solution 1:
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int N = in.nextInt();
if(N>=2||N<=20){
for(int i=1;i<=10;i++){
System.out.println(N+" x "+i+" = "+N*i );
}
}
}
}
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Solution 2
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int N = in.nextInt();
for(int i = 1; i <=10; i++)
{
System.out.println(N + " x "+i+" = "+i*N);
}
}
}
