Python If-Else-HackerRank Solution

0


Given an integer,n, perform the following conditional actions:


  • If n is odd, print Weird
  • If n is even and in the inclusive range of 2 to 5, print Not Weird
  • If n is even and in the inclusive range of 6 to 20, print Weird
  • If n is even and greater than 20, print Not Weird



Input Format


A single line containing a positive integer,n.


Output Format


Print Weird if the number is weird. Otherwise, print Not Weird.


Sample Input 0



 3


Sample Output 0



 Weird



Explanation 0


n = 3

n is odd and odd numbers are weird, so print Weird.


Sample Input 1



 24


Sample Output 1



 Not Weird



Explanation 1


n = 24

n>20 and n is even, So it is not weird


Solution 


    import math
    import os
    import random
    import re
    import sys


    def wierd(n):
       if n % 2 == 1 or 6 <= n <= 20:
       print('Weird')
       else:
       print('Not Weird')


    wierd(int(input()))



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