We are going to solve pigIt challenge from the codewars. pigIt function accept a String which is str as an argument. So the string argument has to be translated into Pig Latin. For this we need to perform the following:
- Move the first letter of the word to the end of the word.
- Add "ay" to the end of the word.
- If the string is a punctuation mark or a number, leave it as is. Leave the cases of the words untouched.
Move the first letter of each word to the end of it, then add "ay" to the end of the word. Leave punctuation marks untouched.Examples:
pigIt('Pig latin is cool'); // igPay atinlay siay oolcay
pigIt('Hello world !'); // elloHay orldway !
Simple Pig Latin Java
import java.util.regex.Pattern;
public class PigLatin {
public static String pigIt(String str) {
if(str == null || str.length()==0){
return null;
}
final String []words = str.split("\\s");
final StringBuffer pigLatin = new StringBuffer();
for(String s :words){
if(Pattern.matches("\\p{IsPunctuation}",s)){
pigLatin.append(s).append(" ");
}
else{
pigLatin.append(s.substring(1)).
append(s.charAt(0)).
append("ay ");
}
}
while (pigLatin.charAt(finalWords.length() - 1) == ' ') {
pigLatin.setLength(pigLatin.length() - 1);
}
return new String(pigLatin);
}
}
Simple pig Latin JavaScript
function pigIt(str){
let words = str.split(' ');
let pigLatin = [];
for(let word of words){
if((/([a-zA-Z])/).test(word)){
pigLatin.push(word.substring(1) + word[0] + "ay");
}else{
pigLatin.push(word);
}
}
return pigLatin.join(" ");
}
Simple Pig Latin Python
def pig_it(text):
'''Converts text into pig-latin'''
words = text.split(' ')
pigLatin = ' '
for word in words:
if word in '!.%&?':
pigLatin = pigLatin + word
else:
pig_word = word[1:] + word[0] + 'ay'
pigLatin = pigLatin + pig_word + ' '
return pigLatin.strip(' ')
